Exercise 3.4 — SASAA Construction

Construction when two adjacent sides and three angles are given.

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Exercise 3.4 – Construction of Quadrilaterals (S.A.S.A.A.) | Class 8 Maths

Constructing a Quadrilateral Using the S.A.S.A.A. Method

Exercise 3.4 of the Class 8 Mathematics chapter on Construction of Quadrilaterals (CBSE, Telangana, and Andhra Pradesh syllabi) focuses on a specific but very important case: constructing a quadrilateral when two adjacent sides and three angles are known. This is called the S.A.S.A.A. method — Side, Angle, Side, Angle, Angle.

A quadrilateral has four sides and four angles, but you only need five independent measurements to pin it down uniquely. The S.A.S.A.A. set — two neighbouring sides and three of the four angles — provides exactly those five values. The fourth angle is always recoverable from the angle-sum property.

Angle-Sum Property of a Quadrilateral: The four interior angles of any quadrilateral always add up to 360°. If three angles are known, the fourth = 360° − (sum of the three known angles).
∠A + ∠B + ∠C + ∠D = 360°

Problem (a) — Quadrilateral HELP

Question (a)

Construct quadrilateral HELP with HE = 6 cm, EL = 4.5 cm, ∠H = 60°, ∠E = 105°, and ∠P = 120°.

Step 0 – Find the Missing Angle

Three of the four angles are given. Before picking up a ruler, always find the fourth angle using the angle-sum property. This prevents errors during construction.

∠L = 360° − (∠H + ∠E + ∠P)
∠L = 360° − (60° + 105° + 120°)
∠L = 360° − 285°
∠L = 75°

Given Data at a Glance

ElementValueRole in Construction
HE6 cmFirst base side — drawn first
EL4.5 cmSecond adjacent side — marked with compass
∠H60°Angle at H — ray HY drawn here
∠E105°Angle at E — ray EX drawn here
∠P120°Given; used as cross-check
∠L75° (calculated)Ray LZ drawn here to locate P

Rough Sketch

H E L P 6 cm 4.5 cm 60° 105° 75° 120° Y X Z
Rough sketch of quadrilateral HELP showing all given angles and sides

Steps of Construction — HELP

  1. Draw a line segment HE = 6 cm. This is your base.
  2. At vertex E, draw ray EX making an angle of 105° with HE, using a protractor.
  3. With E as centre and radius 4.5 cm, draw an arc that cuts ray EX at point L.
  4. At vertex H, draw ray HY making an angle of 60° with HE, on the same side as L.
  5. At vertex L, draw ray LZ making an angle of 75° with LE (the calculated ∠L). This ray should go towards ray HY.
  6. The point where ray LZ meets ray HY is vertex P. Join all vertices — HELP is the required quadrilateral.
Why draw ∠L = 75° and not ∠P = 120°? Because L lies on the already-drawn side EL, making it easier to set the angle precisely. Once P is located by the intersection, you can verify that ∠P = 120° as a check.
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Problem (b) — Parallelogram GRAM

Question (b)

Construct parallelogram GRAM with GR = AM = 5 cm, RA = MG = 6.2 cm, and ∠R = 85°.

Key Properties of a Parallelogram Used Here

  • Opposite sides are equal — GR = AM = 5 cm and RA = MG = 6.2 cm (already given)
  • Opposite angles are equal — ∠R = ∠M = 85°
  • Adjacent angles are supplementary — ∠G + ∠R = 180°, so ∠G = ∠A = 180° − 85° = 95°
∠R = ∠M = 85° (opposite angles of a parallelogram)
∠G = ∠A = 180° − 85° = 95° (co-interior / adjacent angles)

Given Data at a Glance

ElementValueSource
GR5 cmGiven — base of construction
RA6.2 cmGiven — marked from R
∠R85°Given
∠A95°Calculated (adjacent to ∠R)
∠G95°Calculated (equal to ∠A)
∠M85°Calculated (equal to ∠R)

Rough Sketch

G R A M 5 cm 5 cm 6.2 cm 6.2 cm 95° 85° 95° 85°
Rough sketch of parallelogram GRAM — all angles derived from ∠R = 85°

Steps of Construction — GRAM

  1. Draw line segment GR = 5 cm as the base.
  2. At R, draw ray RX making an angle of 85° with GR.
  3. With R as centre and radius 6.2 cm, mark point A on ray RX.
  4. At A, draw ray AY making an angle of 95° with RA (going towards G's side).
  5. At G, draw ray GZ making an angle of 95° with GR.
  6. The intersection of rays AY and GZ gives point M. Join all four vertices — GRAM is complete.

Problem (c) — Rectangle FLAG

Question (c)

Construct rectangle FLAG with sides FL = 6 cm and LA = 4.2 cm.

Key Properties of a Rectangle Used Here

  • All angles are 90° — ∠F = ∠L = ∠A = ∠G = 90°
  • Opposite sides are equal and parallel — FL = AG = 6 cm; LA = FG = 4.2 cm
  • A rectangle is a special parallelogram, so the S.A.S.A.A. method applies directly with all angles fixed at 90°

Given Data at a Glance

ElementValueSource
FL6 cmGiven — base
LA4.2 cmGiven — adjacent side
AG6 cmOpposite side (equal to FL)
FG4.2 cmOpposite side (equal to LA)
∠F = ∠L = ∠A = ∠G90° eachProperty of rectangle

Rough Sketch

F L A G 6 cm 6 cm 4.2 cm 4.2 cm
Rough sketch of rectangle FLAG — all four corners are 90° right angles

Steps of Construction — FLAG

  1. Draw line segment FL = 6 cm as the base.
  2. At L, draw ray LX making an angle of 90° with FL using a protractor or set-square.
  3. With L as centre and radius 4.2 cm, mark point A on ray LX.
  4. At A, draw ray AY making an angle of 90° with LA (going towards F's side).
  5. At F, draw ray FZ making an angle of 90° with FL.
  6. The intersection of rays AY and FZ gives point G. Join all four vertices — FLAG is the required rectangle.

Common Mistakes to Avoid in Exercise 3.4

  • Skipping the angle-sum step — Always calculate the missing angle before starting. Drawing without it leads to a shape that won't close.
  • Wrong angle direction — All rays must be drawn on the same side of the base line. If you flip one angle, P or M will land on the wrong side.
  • Compass radius set incorrectly — Double-check the compass opening against your ruler before marking EL or RA. A 0.5 mm error compounds into a visible gap.
  • Not using a sharp pencil — Thick pencil lines make intersection points ambiguous. Use a well-sharpened HB pencil for accurate constructions.
  • Parallelogram property errors — In problem (b), students sometimes forget that ∠G = 95° (not 85°). Adjacent angles in a parallelogram are supplementary, not equal.
  • Rectangle shortcut error — While opposite sides could be marked with a compass, it is faster and more accurate to draw 90° rays at every vertex using a set-square. Confirm all four angles before submitting.

What This Exercise Prepares You For

Mastering S.A.S.A.A. constructions builds a precise geometric intuition that is tested directly in board exams for CBSE Class 8, and in Telangana and Andhra Pradesh state board assessments. The skills practised here — working with angle properties of special quadrilaterals, using the angle-sum rule, and accurately operating a compass and protractor — reappear throughout secondary mathematics.

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